Answer:
P ( 3, - pi/3 + 2 pi n) or P ( -3 , -pi/3 + pi(2 n +1))
Step-by-step explanation:
P ( 3, - pi/3)
We can circle 2pi n around the circle and be back at the same polar coordinate
P ( 3, - pi/3 + 2 pi n)
or we can flip the radius to a negative and add pi to the theta
P ( -3, - pi/3 + pi)
Then we can circle 2pi n around the circle and be back at the same polar coordinate
P ( -3 , -pi/3 + 2 pi n +pi)
P ( -3 , -pi/3 + pi(2 n +1))
