Answer:
[tex]\boxed{\sf B \ and \ C}[/tex]
Step-by-step explanation:
The triangle is a right triangle.
We can use trigonometric functions to solve.
[tex]\sf sin(\theta)=\frac{opposite}{hypotenuse}[/tex]
[tex]\sf sin(60)=\frac{5.2}{KL}[/tex]
[tex]\sf KL=\frac{5.2}{sin(60)}[/tex]
[tex]\sf sin(90-60)=\frac{3}{KL}[/tex]
[tex]\sf KL=\frac{3}{sin(90-60)}[/tex]
