Answer:
The rule of the transformation is 6 units up and 3 units to the right [tex]T_{(3, \ 6)}[/tex] and an horizontal dilation of 2 as well as a vertical dilation of 4.
Step-by-step explanation:
The given coordinates of EFG and E'F'G' from the chart are;
E(3, 2)
F(9, 5)
G(9, 2)
E'(6, 8)
F'(18, 20)
G'(18, 8)
Therefore, we have, given that the y-coordinates of E and G are the same, the length of segment EG = 9 - 3 = 6 units
Similarly, given that the x-coordinates of F and G are the same, the length of segment FG = 5 - 2 = 3 units
The length of segment FE = [tex]l = \sqrt{\left (y_{2}-y_{1} \right )^{2}+\left (x_{2}-x_{1} \right )^{2}}[/tex] which gives;
Length from E(3, 2) to F(9, 5) = [tex]l = \sqrt{\left (5-2 \right )^{2}+\left (9-3 \right )^{2}} = 3 \cdot \sqrt{5}[/tex]
For similarly oriented E'F'G', we have;
E'G' = 18 - 6 = 12
F'G' = 20 - 8 = 12
E'F' = 12·√2
Therefore, the transformation is 6 units up and 3 units to the right and an horizontal dilation of 2 as well as a vertical dilation of 4.
