Answer: The number of sets contain any 4 numbers = 210
Step-by-step explanation:
Given: Universal set = {0,1,2,3,4,5,6,7,8,9}.
i.e. Total choices = Numbers in set = 10
By combinations, the number of sets contain any 4 numbers =[tex]^{10}C_4[/tex]
[tex]=\dfrac{10!}{4!6!}\ \ \ \ \ [^nC_r=\dfrac{n!}{r!(n-r)!}]\\\\=\dfrac{10\times9\times8\times7\times6!}{4\times3\times2\times1 \times6!}\\\\=210[/tex]
Hence, the number of sets contain any 4 numbers = 210
