Answer:
D. F(x) = ( (1/5)x)^2 - 4
Step-by-step explanation:
The standard transformation with a stretch and a shift is
F(x) = f(x/b) + k
The red curve has a vertex at (0,-4), and cuts the x-axis at (10,0)
That means that before the vertical shift (of k=-4), the vertex was at (0,0), and the curves passes through (10,4).
Substituting in the equation
F(10) = (10/b)^2 -4 = 0
solve for b
(10/b)^2-4 = 0
(10/b)= sqrt(4) = 2
b = 10/2 = 5
Therefore the transformation equation is
F(x) = (x/5)^2-4
The answer is
F(x) = ( (1/5)x)^2 - 4
