Answer:
yes,
Step-by-step explanation:
Homeomorphic sets :-
Two sets are homeomorphic if define a function f between both sets which is satisfy the following conditions:
[tex](i)[/tex] Function f is a bijection (one-to-one and onto),
[tex](ii)[/tex] Function f is continuous,
[tex](iii)[/tex] Inverse function of f is also continuous.
example:
Let [tex]f:[0, 2\pi)\rightarrow s^1[/tex]given by [tex]f(x)=(\cos x, \sin x)[/tex] where [tex]f(x)[/tex] is a continuous and bijection fuction but inverse of fuction f is discontinuous.
Hence, set [tex][0,2\pi)[/tex] and [tex]s^1[/tex] are not homeomorphic.
