g(h(x))=?
g(x)= squareroot of x + 1 h(x)= 4x^2
Answer:
g(h(x)) = 2x + 1
Step-by-step explanation:
[tex]g(x)=\sqrt{x} + 1\\h(x) = 4x^2\\[/tex]
To calculate g(h(x)), we should substitute x in g(x) with our 2nd function, h(x). Basically, saying that x = h(x)
[tex]g(x)=\sqrt{x} + 1\\\\g(h(x))=\sqrt{4x^2} + 1 = \sqrt{4} * \sqrt{x^2} + 1 = 2 *x + 1 = 2x+1[/tex]
Answer: 2x + 1