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A 2.0ohm resistor dissipates 50 W of power.
a. Find the current through the resistor, and the voltage across it.
b. Find the energy consumption in kWh for 72 hours.

Respuesta :

Answer:

a) Finding current:

P=I²R

I=√(P/R)=√(50/2)=√25=5.0A

finding voltage:

V=IR( from ohms law)

V= 5.0×2.0=10.0V

b) E=Pt

=(50/1000)×72=3.6kWh

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