Answer: Molar heat capacity C = 136.09 JK-1mole-1
Explanation:
Heat capacity, C = Q/ ΔT
where C = heat capacity
Q =heat energy= Q = 330 J
ΔT is temperature difference =Change in temp =
ΔT = (28.7 +273)-( 21 + 273)= 7.7 K
But
No. of moles of benzene= mass / molar mass
= 24.6g / 78.11g/mol
= 0.3149 moles
Molar heat capacity C = Q/ nΔT
= 330 / ( 0.3149 x 7.7 )
= 136.09 JK-1mole-1