Answer:
no real zeros
imaginary zeros : ±4i
Step-by-step explanation:
f(x) = x^2 + 16
Set equal to zero
0 = x^2 +16
Subtract 16 from each side
-16 = x^2
We have no real zeros
We have imaginary zeros
Taking the square root of each side
sqrt(-16) = sqrt(x^2)
±4i = x
