Need help with part b. Thanks!
Answer:
[tex](x-4)^{2}[/tex]>0
[tex](x-4)^{2}[/tex]+4>0
so the function is always positive.
Step-by-step explanation:
As [tex](x-4)^{2}[/tex] always positive, because when you square numbers you will get always a positive number.
So [tex](x-4)^{2}[/tex]+4>0, because the (+4) will not effect the answer as (x-4)^{2} will be positive.