[tex]a = \frac{v - u}{t} [/tex]
v = final velocity
u = initial velocity
t = time taken
the acceleration of the cyclist is
[tex] \frac{10 - 0}{3} = 3.333333....[/tex]
approximately 3.33 m/s^2
the acceleration of the car is
[tex] \frac{40 - 0 }{8} = 5.0[/tex]
5.0 m/s^2
[tex]5.0 > 3.33 \\ so \: the \: answer \: is \: no[/tex]
