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Suppose you are bending stainless steel wire to make the earring shown below. The
triangular portion of the earring is an isosceles triangle. If 1.5 centimeters are needed
to make the hook portion of the earring, how many earrings can be made of 45
centimeters of wire?

Suppose you are bending stainless steel wire to make the earring shown below The triangular portion of the earring is an isosceles triangle If 15 centimeters ar class=

Respuesta :

quasarJose

Given parameters:

Length of earring hook  = 1.5cm

Length of given wire = 45cm

Dimension of the triangle = 3.2cm, 3.2cm and 2.1cm

Unknown:

Number of earrings that can be made from the wire = ?

To solve this problem, we need to calculate the total length of the earring we want to make.

  Total earring length  = Perimeter of earring + length of earring hook

                                      = 3.2 + 3.2 + 2.1 + 1.5  

                                      = 10cm

Now the length of the wire is 45cm,

  Number of earrings  = [tex]\frac{45}{10}[/tex]  = 4.5 earrings

  But this is not reasonable, therefore, we can only forge 4 complete earrings from the given length with 5cm of wire remaining.

The number of earrings that can be made is 4.

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