Answer:
The median is [tex]Median = 0.903[/tex]
Step-by-step explanation:
From the question we are told that Â
  The sample size is n =  100
  The  [tex]1^{st} \to 45^{th}[/tex] measurements is  [tex]= 0.859 \to 0.900[/tex]
  Generally since that after 0.900 we have  0.901 , then the
   [tex]46^{th} \ measurement \ is \ 0.901[/tex]
in the same manner the  [tex]47^{th} \ measurement \ is \ 0.902[/tex],
Given that 0.902 Â was observed three times it means that
                     [tex]47^{th},48^{th},49^{th} \ measurement \ is \ 0.902[/tex],
Given that 0.903 Â was observed two times it means that
                     [tex]50^{th},51^{th} \ measurement \ is \ 0.903[/tex],
Given that 0.903 Â was observed four times it means that
                     [tex]52^{nd},53^{rd},54^{th},55^{th} \ measurement \ is \ 0.904[/tex],
Given that the highest measurement is  0.958 then then the  [tex]56^{th} \to 100^{th} \ measurement \ is \ between \ 0.905 \to 0.958[/tex]
Generally the median is is mathematically represented as
      [tex]Median = \frac{ [\frac{n^{th}}{2}] + [(\frac{n}{2})^{th} + 1 ]}{2}[/tex]
=> Â Â Â Â [tex]Median = \frac{ [\frac{100^{th}}{2}] + [(\frac{100}{2})^{th} + 1 ]}{2}[/tex]
=> Â Â Â Â [tex]Median = \frac{ [50^{th}] + [51^{th} ]}{2}[/tex]
=> Â Â Â Â [tex]Median = \frac{ 0.903 + 0.903}{2}[/tex]
=> Â Â Â Â [tex]Median = 0.903[/tex]
