Answer:
t = 9.36 s
Explanation:
Given that,
Initial velocity, u = 0 (at rest)
Final velocity, v = 77 m/s
Acceleration of the airplane, a = 8.2 m/s²
We need to find the time required for an airplane to take off its speed 77 m/s. Let t be the time. using first equation of motion to find it as follows :
v=u+at
[tex]t=\dfrac{v-u}{a}\\\\t=\dfrac{77}{8.22}\\\\t=9.36\ s[/tex]
so, the airplane will take 9.36 seconds.
