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If 342.2 grams of C12H22O11 (sucrose) is dissolved in 1.0 L of solution. What is the molar concentration of the solution? Report your answer with the correct number of significant figures.

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Neetoo

Answer:

M = 1 M

Explanation:

Given data:

Mass in gram = 342.2 g

Volume of solution = 1.0 L

Molar concentration = ?

Solution:

Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.

Formula:

Molarity = number of moles of solute / L of solution

Number of moles of sucrose:

Number of moles = mass/molar mass

Number of moles = 342.2 g/ 342.2 g/mol

Number of moles = 1 mol

Molarity:

M = 1 mol / 1.0 L

M = 1 mol/L

M = 1 M

The molar concentration of the solution is :

- M = 1 M

Check below to see the full solution.

Molar Concentration

Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.

What information do we have?

Mass in gram = 342.2 g

Volume of solution = 1.0 L

Molar concentration = ?

Number of moles of sucrose:

Number of moles = mass/molar mass

Number of moles = 342.2 g/ 342.2 g/mol

Number of moles = 1 mol

Molarity:

Molarity = number of moles of solute / L of solution

M = 1 mol / 1.0 L

M = 1 mol/L

M = 1 M

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