The amount of Kr is 2547.75 grams.
Volume of cylinder = 8.55 L
Pressure = 8.33 atm
Temperature = 12.3⁰C
It is required to calculate the amount of Kr in grams.
The ideal gas equation is formulated as: PV = nRT.
In this equation, P refers to the pressure of the ideal gas, V is the volume of the ideal gas, n is the total amount of ideal gas that is measured in terms of moles, R is the universal gas constant, and T is the temperature.
We will use the ideal gas equation to calculate the amount of Kr in grams.
The formula of ideal gas equation is shown as
PV= nRT
Where, P refers to the pressure of the ideal gas, V is the volume of the ideal gas, n is the total amount of ideal gas that is measured in terms of moles, R is the universal gas constant, and T is the temperature.
[tex]n = \frac{mass}{molar\ mass}[/tex]
Value of gas constant R = 0.0821 L.atm.K⁻¹ mol⁻¹
We know that molar mass of Kr = 83.79 g/mol
Now, convert the temperature value from Celsius to Kelvin
Temperature = 12.3 + 273 = 285.3 K
Now, put all the given values as
8.33 atm × 8.55 L = mass/ molar mass × 0.0821 L.atm.K⁻¹ mol⁻¹ × 285.3 K
Mass of Kr = [tex]\frac{8.33\times 8.55\times 83.79}{0.0821\times285.3}[/tex]
Mass of Kr = 2547.75 grams.
Hence, the amount of Kr is 2547.75 grams.
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