Answer:
V₁ = 808.9mL
Explanation:
Based on Charles's law, the volume of a sample of gas is directely proportional to its absolute temperature. The formula is:
[tex]\frac{V_1}{T_1} =\frac{V_2}{T_2}[/tex]
Where V is volume and T is absolute temperature of 1, initial state and 2, final state of the gas.
The initial state is:
V₁ = Our incognite
T₁ = 79°C + 273.15 = 352.15K
Final state is:
V₂ = 990.4mL
T₂ = 158°C + 273.15 = 431.15K
Replacing:
[tex]\frac{V_1}{352.15K} =\frac{990.4mL}{431.15K}[/tex]
Considering the Charles's Law, the volume at 79 °C is 808.86 mL.
Charles's Law consists of the relationship that exists between the volume and the temperature of a certain quantity of ideal gas, which is maintained at a constant pressure.
This law says that for a given sum of gas at a constant pressure, as the temperature increases, the volume of the gas increases and as the temperature decreases, the volume of the gas decreases because the temperature is directly related to the energy of the movement they have the gas molecules.
In summary, Charles's law is a law that says that when the amount of gas and pressure are kept constant, the quotient that exists between the volume and the temperature will always have the same value:
[tex]\frac{V}{T}=k[/tex]
Studying two different states, an initial state 1 and a final state 2, it is satisfied:
[tex]\frac{V1}{T1}=\frac{V2}{T2}[/tex]
In this case, you know:
Replacing in Charles's law:
[tex]\frac{V1}{352 K}=\frac{990.4 mL}{431 K}[/tex]
Solving:
[tex]V1=\frac{990.4 mL}{431 K}x352 K[/tex]
V1=808.86 mL
Finally, the volume at 79 °C is 808.86 mL.
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