Answer:
The value is [tex]KE_b =0.710 \ J[/tex]
Explanation:
From the question we are told that
The mass of the bullet is [tex]m_b = 5.00 \ g = 0.005 \ kg[/tex]
The mass of the wood is [tex]m_w = 900 \ g = 0.90\ kg[/tex]
The height attained by the combined mass is [tex]h = 8.0 \ cm = 0.08 \ m[/tex]
Generally according to the law of energy conservation
[tex]KE _b = PE_c[/tex]
Here [tex]KE_b[/tex] is the kinetic energy of the bullet before collision.
and [tex]PE_c[/tex] is the potential energy of the combined mass of bullet and wood at the height h which is mathematically represented as
[tex]PE_m = [m_b + m_w] * g * h[/tex]
So
[tex]KE_b =PE_c = [0.005 + 0.90] * 9.8 *0.08[/tex]
=> [tex]KE_b =0.710 \ J[/tex]
