Answer:
The final speed is 14 m/s and its position is 28.5 m.
Explanation:
The question says "A mobile starts from the origin of the axle system with an initial speed of 5m / s. It moves uniformly accelerated with acceleration 3m / s2. Find out the speed and position of the mobile after a time interval of 3s "
Given that,
Initial speed, u = 5 m/s
Acceleration, a = 3 m/s²
We need to find the final speed and position of the mobile after a time interval of 3s.
For final speed (v)
It can be calculated using first equation of motion as:
v=u+at
v=5+3(3)
v = 14 m/s
Let it is at x distance. Using second equation of motion to find it as follows :
[tex]x=ut+\dfrac{1}{2}at^2\\\\x=5(3)+\dfrac{1}{2}\times 3\times (3)^2\\\\x=28.5\ m[/tex]
Hence, the final speed is 14 m/s and its position is 28.5 m.
