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A 87.0 mL87.0 mL aliquot of a 0.400 M0.400 M stock solution must be diluted to 0.100 M.0.100 M. Assuming the volumes are additive, how much water should be added

Respuesta :

Answer:

Explanation:

Liquid given = 87 mL of .4 M

concentration required = .1 M .

we shall apply the formula

S₁ V₁ = S₂ V₂

S represents concentration and V represents volume

.4 x 87 = .1 V₂

V₂ = 348 mL .

So water to be added = 348 - 87 = 261 mL.

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