Answer:
Explanation:
2CH₃(CH₂)₆CH₃ + 25O₂ = 16CO₂ + 18H₂O.
2 moles         25 moles         18 moles
mol weight of octane = 114
72 g of octane = 72 / 114 = .6316 moles
144 g of oxygen = 144 / 32 = 4.5 moles of oxygen.
2 moles of octane reacts with 25 moles of oxygen
.6316 moles of octant will react with 25 x .6316 / 2 moles of oxygen
= 7.895 moles
So oxygen is the limiting reagent
25 moles oxygen produces 18 moles water
4.5 moles of water produces 18 x 4.5 / 25 moles of water
= 3.24 moles of water
= 3.24 x 18 grams of water
= 58.32 grams of water .
