Answer:
Explanation:
Bridge length A B = 36.5 m
weight W = 2.56 x 10⁵ N acting at middle point that is at 18.25 m from either end.
weight of truck W₁ = 5.25 x 10⁴ N standing at 10.2 m from A .
Let force at A be F₁ and at B be F₂ .
Balancing total upward and downward force
F₁ + F₂ = ( 2.56 + .525 ) x 10⁵ = 3.085 x 10⁵ N
Taking torque of all the forces , for rotational balancing
2.56 x 10⁵ x 18.25 + .525 x 10⁵ x 10.2 = F₂ x 36.5
(46.72 + 5.355 )x 10⁵ = F₂ x 36.5
F₂ = 1.42 x 10⁵ N
F₁ = 1.665 x 10⁵ N
