Using the quadratic formula to solve x2 = 5-x, what are the values of x?
Answer:
its the first choice, negative 1 plus or minus square root of 21 over 2
Step-by-step explanation:
Answer:
A) (-1 ± √21)/ 2
Step-by-step explanation:
Move all terms onto one side
[tex]x^{2}[/tex] = 5-x
[tex]x^{2}[/tex] + x - 5 = 0
Insert values into quadratic formula
a = 1 b= 1 c= - 5
[-b ± √([tex]b^{2}[/tex] - 4ac)]/2a
[-1 ± √([tex]1^{2}[/tex] - 4 (1(-5)]/ 2(1)
(-1 ± √21)/ 2