sujalpanchal401
sujalpanchal401 sujalpanchal401
  • 05-11-2020
  • Mathematics
contestada

find the value of y for which the distance between the points p(2 -3) and q(10 y) is 10 units​

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traceynguyen002
traceynguyen002 traceynguyen002
  • 05-11-2020

Answer:

Step-by-step explanation:

Using the distance formula: distance = [tex]\sqrt{(x_{2} -x_{1})^{2}+(y_{2} -y_{1})^{2} }[/tex]

sub it in,

10 = [tex]\sqrt{(10 -2)^{2}+(y-(-3)^{2}}[/tex]

10 = [tex]\sqrt{(8)^{2} +(y+3)^{2}}[/tex]

10 = [tex]\sqrt{64+y^{2} +9+6y}[/tex]

10 = [tex]\sqrt{73+y^{2} +6y}[/tex]

square both sides:

100 = 73 + [tex]y^{2}[/tex] + 6y

[tex]y^{2}[/tex] + 6y = 27

y( y + 6) = 27

y = 27 OR THE OTHER SOLUTION IS y + 6 = 27

y = 21

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