bachanriya2060 bachanriya2060

05-11-2020
Mathematics

contestada

Find, from first principles,the derivative of e^tanx

Respuesta :

aaalll2029 aaalll2029

05-11-2020

Answer:

[(sec^2)(x)]. [e^tan(x)]

Or

[e^(tan(x))]/[(cos^2)(x)].

Step-by-step explanation:

d/dx(e^tan(x))

From the low:

[(d/du)(e^u)]=[(d/du)(u)]. [ln(e)]. [e^u]

=[(sec^2)(x)]. [e^(tan(x))]. [ln(e)]

=[(sec^2)(x)]. [e^(tan(x))]

or

[e^(tan(x))]/[(cos^2)(x)].

Because

(cos^2)(x)=1 / (sec^2)(x)

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