Given:
[tex]|x-4(72)|=2[/tex]
To find:
The highest and lowest scores Sam could have made in the tournament.
Solution:
We have,
[tex]|x-4(72)|=2[/tex]
[tex]|x-288|=2[/tex]
It can be written as
[tex]x-288=\pm 2[/tex]
Add 288 on both sides.
[tex]x=288\pm 2[/tex]
[tex]x=288-2[/tex] and [tex]x=288+2[/tex]
[tex]x=286[/tex] and [tex]x=290[/tex]
Therefore, the highest and lowest scores Sam could have made in the tournament are 290 and 286 respectively.