A chemist adds 255.0mL of a 1.27M sodium carbonate Na2CO3 solution to a reaction flask. Calculate the mass in grams of sodium carbonate the chemist has added to the flask.

Respuesta :

Answer: The mass in grams of sodium carbonate is 34.3 g

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

[tex]Molarity=\frac{n\times 1000}{V_s}[/tex]

where,

n = moles of solute

[tex]V_s[/tex] = volume of solution in ml

moles of [tex]Na_2CO_3[/tex] = [tex]\frac{\text {given mass}}{\text {Molar mass}}=\frac{xg}{106g/mol}[/tex]

Now put all the given values in the formula of molarity, we get

[tex]1.27=\frac{xg\times 1000}{106g/mol\times 255.0 ml}[/tex]

[tex]x=34.3g[/tex]

Therefore, the mass in grams of sodium carbonate is 34.3 g