Answer:
[tex]\phi=\dfrac{q}{6\epsilon_o}[/tex]
Explanation:
A point charge Q is placed at the center of a cube of side l.
We need to find the flux through one face of the cube. Let the flux is [tex]\phi[/tex].
There are 6 faces in a cube.
According to Gauss's law, net flux is given by :
[tex]\phi=\dfrac{q}{\epsilon_0}[/tex]
As there are 6 faces of a cube, flux through one surface is :
[tex]6\phi=\dfrac{q}{\epsilon_o}\\\\\phi=\dfrac{q}{6\epsilon_o}[/tex]
So, the flux through one face of the cube is [tex]\dfrac{q}{6\epsilon_o}[/tex].
