A bicycle starts at 2.5m/s and accelerates along a straight path to a speed of 12.5m/s in a time of 4.5 seconds. What is the bicyclist’s acceleration to the nearest tenth of a m/s^2 ?

Respuesta :

Answer:

The bicyclist's acceleration is 2.2m/s^2

Explanation:

Given

[tex]u = 2.5m/s[/tex] ---- Initial Velocity

[tex]v = 12.5m/s[/tex] ---- Final Velocity

[tex]t = 4.5s[/tex] ---- Time

Required

Determine the acceleration

This will be solved using the first equation of motion

[tex]v = u + at[/tex]

Substitute values for v, u and a

[tex]12.5 = 2.5 + a * 4.5[/tex]

[tex]12.5 = 2.5 + 4.5a[/tex]

Collect Like Terms

[tex]4.5a = 12.5 - 2.5[/tex]

[tex]4.5a = 10.0[/tex]

Solve for a

[tex]a = 10.0/4.5[/tex]

[tex]a = 2.2m/s^2[/tex] ---- (approximated)

Hence, the bicyclist's acceleration is 2.2m/s^2

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