Answer:
The velocity is [tex]v = 12 \ m/s[/tex]
Explanation:
From the question we are told that
The horizontal force is [tex]F_h = 310 \ N[/tex]
The mass of the ball is [tex]m_b = 2.0 \ kg[/tex]
The radius of the circle is [tex]r = 0.90 \ m[/tex]
Generally the centripetal force acting on the ball is mathematically represented as
[tex]F_r = m \frac{v^2}{r}[/tex]
Making v the subject
[tex]v = \sqrt{\frac{r * F_r}{m} }[/tex]
Generally the centripetal force is equivalent to the horizontal force exerted so
[tex]F_r = F_h = 310 \ N[/tex]
=> [tex]v = \sqrt{\frac{0.90 * 310 }{ 2} }[/tex]
=> [tex]v = 12 \ m/s[/tex]
