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What is the percent composition of all the elements of sucrose, C12, H22 and O11?please be specific..​

Respuesta :

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There are completely ( 12 + 22 + 11 = 45 ) elements .

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(( C )) percentage :

[tex] \frac{12}{45} \times 100 = \frac{4}{15} \times 100 = 26.666 \: \: percent \\ [/tex]

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(( H )) percentage :

[tex] \frac{22}{45} \times 100 = 48.888 \: \: percent \\ [/tex]

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(( O )) percentage :

[tex] \frac{11}{45} \times 100 = 24.444 \: \: percetage \\ [/tex]

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