Calculate the standard biological Gibbs free energy for the reaction: pyruvate- + NADH + H+(aq) ---> Lactate- + NAD+ at 309 K given that the standard Gibbs free energy = -65.0 kJ/mol at this temperature. This reaction occurs under conditions of low oxygen supply, such as in muscle cells during strenuous exercise. Note: See Box 7.1 on page 164. The biological standard state has hydrogen ions at 1x10-7 molar instead of 1 M.

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boffeemadrid boffeemadrid · Answer 1 · 2020-11-10T18:45:23+01:00

Answer:

[tex]-23592.19\ \text{J/mol}[/tex]

Explanation:

T = Temperature = 309 K

[tex]\Delta G^{\circ}[/tex] = Standard Gibbs free energy = -65.0 kJ/mol

R = Gas constant = 8.314 J/mol K

[tex][H^+][/tex] = Biological standard state has hydrogen ions = [tex]10^{-7}\ \text{molar}[/tex]

Reaction quotient is given by

[tex]Q=\dfrac{1}{[H^+]}\\\Rightarrow Q=\dfrac{1}{10^{-7}}\\\Rightarrow Q=10^7[/tex]

Standard biological Gibbs free energy is given by

[tex]\Delta G=\Delta G^{\circ}+RT\ln Q\\\Rightarrow \Delta G=-65000+8.314\times 309\times \ln10^7\\\Rightarrow \Delta G=-23592.19\ \text{J/mol}[/tex]

The standard biological Gibbs free energy of the reaction is [tex]-23592.19\ \text{J/mol}[/tex]