How do I find the missing sides on this special triangle?
Answer:
x = 6
y = [tex]3\sqrt{2}[/tex]
Step-by-step explanation:
Thats a 45 45 90 triangle, one of my favorite and you'll come to miss it later because of how easy it is.
See the file provided for the trick
Because [tex]3\sqrt{2}[/tex] falls where a 1 is in the diagram that means y is also [tex]3\sqrt{2}[/tex] because you multiply [tex]3\sqrt{2}[/tex] by 1, and to get x you'll multiply the value we're given, [tex]3\sqrt{2}[/tex], by the value in the spot in the given diagram, [tex]\sqrt{2}[/tex].
[tex]3\sqrt{2}[/tex] ×[tex]\sqrt{2}[/tex]
Note; a radical multiplied by itself is the value in the radical
Therefore,
[tex]3\sqrt{2}[/tex] ×[tex]\sqrt{2}[/tex] = 3(2) = 6
Thus x = 6
The explanation for this;
[tex]\sqrt{2}[/tex] * [tex]\sqrt{2}[/tex] = [tex]\sqrt{2}^2[/tex]
And if you square a square root you have its square root times its square root squared, which if it was [tex]\sqrt{4}^2[/tex] it'd ultimately be [tex](2)^2[/tex] which is 2x2 which equals 4
Hope this helps