Answer:
(i) a∗b=a−b
Check commutative is
a∗b=b∗a
a∗b=a−b
b∗a=b−a
Since, a∗b
=b∗a
∗ is not commutative.
Check associative
∗ is associative if
(a∗b)∗c=a∗(b∗c)
(a∗b)∗c=(a−b)
∗
c=(a−b)−c=a−b−c
a∗(b∗c)=a∗(b−c)=a−(b−c)=a−b+c
Since (a∗b)∗c
=a∗(b∗c)
Step-by-step explanation:
