Answer:
P=0.0000037
P=0.00037%
Step-by-step explanation:
Probability
A standard deck of 52 playing cards has 4 aces.
The probability of getting one of those aces is
[tex]\displaystyle \frac{4}{52}=\frac{1}{13}[/tex]
Now we got an ace, there are 3 more aces out of 51 cards.
The probability of getting one of those aces is
[tex]\displaystyle \frac{3}{51}=\frac{1}{17}[/tex]
Now we have 2 aces out of 50 cards.
The probability of getting one of those aces is
[tex]\displaystyle \frac{2}{50}=\frac{1}{25}[/tex]
Finally, the probability of getting the remaining ace out of the 49 cards is:
[tex]\displaystyle \frac{1}{49}[/tex]
The probability of getting the four consecutive aces is the product of the above-calculated probabilities:
[tex]\displaystyle P= \frac{1}{13}\cdot\frac{1}{17}\cdot\frac{1}{27}\cdot\frac{1}{49}[/tex]
[tex]\displaystyle P= \frac{1}{270,725}[/tex]
P=0.0000037
P=0.00037%
