faresbinsaroor
faresbinsaroor faresbinsaroor
  • 04-10-2016
  • Mathematics
contestada

write a quadratic equation in standard form with roots -2 and -5

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mpanderla95
mpanderla95 mpanderla95
  • 04-10-2016
To solve this problem. First lets work our way backwards and try to figure out the binomials that will result in these roots.

-2 root = X int = -2
Thus it would be (X +2) because if you solve for x the solution or X intercept is -2.
Same thing for -5.
(X+5).

Next place them together and multiply or foil to obtain the quadratic.

Y = (X+5)(X+2)
Y = X^2 + 7x + 10

Standard form = Ax^2 +/- Bx +/- C = 0.

The standard form is X^2 + 7x + 10.
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