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  • 05-10-2016
  • Chemistry
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how many moles of Fe2o3 are in 161 g of the compound ?

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  • 05-10-2016
m = 161g
M = 56 * 2 + 16 * 3 = 160g/mol

n = m/M = 161g / 160g/mol = 1,00625 mol
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