sum of geometric sequence
for the sum where the initial value is a₁ and the common ratio is r and the term is n
[tex]S_n= \frac{a_1(1-r^n)}{1-r} [/tex]
1/6, 3/6, 9/6
hmm
times 3 every time
common ratio is 3
a₁=1/6
n=15
[tex]S_15= \frac{(1/6)(1-3^15)}{1-3} [/tex]
[tex]S_15= \frac{(1/6)(1-14348907)}{-2} [/tex]
[tex]S_15= \frac{(1/6)(-14348906)}{-2} [/tex]
[tex]S_15= \frac{-2391484.33333333}{-2} [/tex]
[tex]S_15= 1195742.16666666 [/tex]
answer is 1195742.16666666 or your last answer
