ccolburn1 ccolburn1
  • 03-12-2020
  • Mathematics
contestada

. An object is launched straight up into the air. It is launched from a height
of H feet off the ground. Its height H, in feet, at t seconds is given by the
equation H = -8t^2 + 40t + 18. Find all times t that the object is at a height
of 50 feet off the ground.

Respuesta :

nasir21606 nasir21606
  • 03-12-2020

Answer:

H=24

Step-by-step explanation:

Answer Link

Otras preguntas

What is the solution to this system of linear equations: y-x=4 and y+2x=1 1) (-1,3) 2) (0,4) 3) (1,-1) 4) (-3,3)
What are 2 numbers that when multiplied together you get 360 and when added together you get -96
20% of my money is £2.55 What is 2/5 of it?
What is the solution to this system of linear equations: y-x=4 and y+2x=1 1) (-1,3) 2) (0,4) 3) (1,-1) 4) (-3,3)
A certain test is worth 155 points. How many points (rounded to the nearest point) are needed to obtain a score of 65%?
what percentage of 1457 is 898?
If x^5y^4z^2 <0 , which of the following must be true? I xy <0 II yz <0 III xz <0
How is carbon dioxide obtained?
The diagram shows a patio in the shape of a rectangle. The patio is 3.6m long and 3m wide. Mathew is going to cover the patio with paving slabs. Each paving sla
When was the battle of Hastings?