Complete question is;
A projectile is fired upward from the ground with a velocity of 250 feet
per second. Neglecting air resistance, the height of the projectile in feet at
any time t, in seconds, can be described by the polynomial function P(t) = -16t² + 250t. Find the height at t = 4 seconds
Answer:
744 ft
Step-by-step explanation:
We are told that the height of the rocket is represented by the polynomial P(t) = -16t² + 250t
Where t is time in seconds.
Now, we want to Find the height at t = 4 seconds
Thus;
P(4) = -16(4²) + 250(4)
P(4) = -256 + 1000
P(4) = 744 ft