Answer:
two answers: positive 3 and negative 1/4
Step-by-step explanation:
1). move all parts of the problem to one side of the equations. 4x^2-11x=3 subtract 3 from both sides of the equation to get 4x^2-11x-3=0
2). you can now use the quadratic equation to solve the problem (-b+/-sqrt(b^2-4ac))/2a A is the coefficient of x^2 B is the coefficient of x and C is the integer value, so A= 4 B= -11(negative 11) C= -3 (negative 3)
3). solve the quadratic equation using those values.
(11+/-sqrt(11^2-4*4*-3))/2*4
(11+/- sqrt(121-(-48))/8
(11+/- sqrt(169))/8
(11+/- 13)/8
now the equations splits into 2 different equations: (11+13)/8 and (11-13)/8
(11+13)/8 => 24/8 =3
(11-13)/8 => -2/8 =-1/4
