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4. The length of a rectangle is eight more than
twice its width. The perimeter is 96 feet. Find
the dimensions of the rectangle.

Respuesta :

Answer:

length = 104/3 ft

width = 40/3 ft

Step-by-step explanation:

Variables:

L = length

w = width

Set up equations:

  • L = 8 + 2w
  • 2L + 2w = 96

Substitute L with the first bullet point equation:

2L + 2w =  96

2(8 + 2w) + 2w = 96

16 + 4w + 2w = 96

16 + 6w = 96

6w = 80

w = 40/3 ft

Find L now that you have the value of the width:

L = 8 + 2w

L = 8 + 2(40/3)

L = 8 + 80/3

L = 104/3 ft

Final Values:

length = 104/3 ft

width = 40/3 ft

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