Answer:
1) Subtracting one from the other
2) x = 0.375 and y = 0.125
Step-by-step explanation:
Equation 1 :
[tex]\frac{2x+1}{2y}=7\\\\[/tex]
Equation 2:
[tex]\frac{6x-1}{2y}=5[/tex]
To solve these equations by the Elimination method we multiply equation 1 with 6 and multiply equation 2 with 2 so now,
[tex]\frac{2x+1}{2y} =7\\\\2x+1=14y\\\\Multiplying\ Equation\ 1\ with\ 6\\\\12x+6=84y[/tex]
Now for the second equation:
[tex]\frac{6x-1}{2y}=5\\\\6x-1=10y\\\\Multiplying\ equation\ 2\ with\ 2 \\\\12x-2=20y[/tex]
Now subtracting equation 2 from equation 1
[tex]12x+6=84y\\\\12x-2=20y\\\\Subtracting\ leads\ to\\12x-12x+6-(-2)=84y-20y\\0+8=64y\\8=64y\\8/64=y\\0.125=y[/tex]
now insert this value of y into any equation
lets insert it into equation 1
[tex]\frac{2x+1}{2y} =7\\\\2x+1=14y\\2x+1=14(0.125)\\2x+1=1.75\\2x=1.75-1\\2x=0.75\\x=0.75/2\\x-0.375[/tex]
