find the measure of each angle acute angle in a right triangle where the measure of one acute angle is twice the difference of the measure of the other acute angle and 12​

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Answer:

The measures of the acute angles are 38 and 52 degrees.

Step-by-step explanation:

In a right triangle, there are three angles, a right angle and two acute angles. In every traingle, the sum of the measures of the angles is 180 degrees. Let's call the acute angles [tex]a[/tex] and [tex]b[/tex].

[tex]a + b +90 = 180[/tex]

The problem also says that one angle is twice the difference of the other angle and 12. That would look like this:

[tex]a = 2(b-12)[/tex]

Now we have two equations. If we simplify them, we get these:

[tex]\left \{ {{a=90-b} \atop {a=2b-24}} \right.[/tex]

Now you can substitute [tex]a[/tex] in the first equation for [tex]a[/tex] in the second equation

[tex]90-b=2b-24[/tex]

Add [tex]b[/tex] to both sides of the equation

[tex]90 = 3b-24[/tex]

Add [tex]24[/tex] to both sides

[tex]114 = 3b[/tex]

Divide both sides by 3

[tex]38 = b[/tex]

Now, you can substitute [tex]38[/tex] for [tex]b[/tex] in the first equation and simplify.

[tex]a = 90-38[/tex]

[tex]a=52[/tex]

Therefore,

[tex]a=52[/tex], and [tex]b=38[/tex]

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The value of the angles are 38° and 52° respectively

Let the acute angles be represented by a and b.

Based in the information given,

a = 2(b - 12)

a = 2b - 24.

Note that the angle in an acute angle equals to 90°.

Therefore,

a = 90 - b.

a = 2b - 24

Equate the equations together

90 - b = 2b - 24

2b + b = 90 + 24

3b = 114

b = 114/3

b = 38

Therefore, a will be:

= 90° - 38° = 52°

The value of the angles are 38° and 52° respectively.

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