Answer:
ΔL = [tex]\frac{L_{o} }{h_{o} }[/tex] Δh
since the length of the carriages is greater than their height, the length expansion is greater than the height expansion
Explanation:
This is an exercise in thermal expansion, which is described by the expression for one dimension
ΔL = α L₀ ΔT
For the analysis of this exercise we will assume that the sides are independent
Let's look for the condition of the length of the car
ΔL / L₀ = α ΔT
The height delay (h) is
Δh / h₀ = α ΔT
we can match the two expressions
ΔL / L₀ = Δh / h₀
ΔL = [tex]\frac{L_{o} }{h_{o} }[/tex] Δh
since the length of the carriages is greater than their height, the length expansion is greater than the height expansion