contestada

Methane CH4 gas and oxygen O2 gas react to form carbon dioxide CO2 gas and water H2O vapor. Suppose you have 11.0 mol of CH4 and 7.0 mol of O2 in a reactor. Suppose as much as possible of the CH4 reacts. How much will be left? Round your answer to the nearest 0.1 mol

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onyebuchinnaji

Answer:

The number of moles of CHâ‚„ that will remain is 7.5 moles

Explanation:

Complete combustion reaction of oxygen and methane is given as;

CH₄ + 2O₂ → CO₂ + 2H₂O

comparing the number of moles of methane and oxygen in the reaction above, the amount of methane used in the reaction is calculated as follows;

2 moles of O₂   -----------> 1 mole of CH₄  

7 moles of Oâ‚‚ ------------> x moles of CHâ‚„

x = 7 / 2

x = 3.5 moles of CHâ‚„

Total moles of CHâ‚„ in the reactor = 11.0 moles

The number of moles that will remain = 11.0 moles - 3.5 moles

The number of moles that will remain = 7.5 moles

Therefore, the number of moles of CHâ‚„ that will remain is 7.5 moles

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