Answer:
x=2, y=1
Step-by-step explanation:
since they are both congruent, the corresponding sides are also congruent
Thus:
2x+1=x+3
x+y=3x-3y
First, solve 2x+1=x+3
[tex]2x+1=x+3[/tex]
Subtract both sides by x
[tex]2x-x+1=x-x+3\\[/tex]
[tex]x+1=x+3[/tex]
Subtract both sides by 1
[tex]x+1-1=x+3-1[/tex]
[tex]x=2[/tex]
Thus x=2
Next, solve for x+y=3x-3y
[tex]x+y=3x-3y[/tex]
Substitute x with 2 (from the first part)
[tex]2+y=3(2)-3y[/tex]
[tex]2+y-y=6-3y-y[/tex]
[tex]2=6-4y[/tex]
[tex]2-6=6-4y-6[/tex]
[tex]\frac{-4=-4y}{-4}[/tex]
[tex]y=1[/tex]
Thus y=1
