Answer:
-sin(2θ) = (-√3)/2
sin(2θ) = √3/2
2θ = 2kpi + pi/3
i : θ = kpi + pi/6
2θ = 2kpi + pi - pi/3
ii : θ = kpi + 2pi/3
Both i , ii are general solutions.
Specific solution on [0 , 2pi] :
θ = pi/6 , 7pi/6 , 2pi/3 , 5pi/3
Step-by-step explanation:
