According to the equation
HCl + NaOH → NaCl + H2O,
the total number of moles of HCl that can be
neutralized by 80 grams of NaOH is


Respuesta :

Neetoo

Answer:

2 moles of HCl.

Explanation:

Given data:

Mass of NaOH = 80 g

Number of HCl neutralized by NaOH = ?

Solution:

Chemical equation:

NaOH + HCl         NaCl + H₂O

Number of moles of NaOH:

Number of moles = mass/ molar mass

Number of moles = 80 g/ 40 g/mol

Number of moles = 2 mol

Now we will compare the moles of NaOH and HCl,

               NaOH       :         HCl

                   1            :           1

                 2             :            2

Thus, 2 moles of HCl will neutralized by 80 gram of NaOH.